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PROFORM PERFECT LAUNCH DRAG PRACTICE DRAG RACING TREE REACTION TIME TRIGGER

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18d 23h 2m

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drag racing reaction times

Help Needed! Can you write a position equation from the following data?

Consider a driver who has just completed a 1/4 mile drag race. Here is the printout of his results:

Reaction Time 0.02 seconds
60 feet mark 1.724 seconds
330 feet mark 5.185 seconds
1/8 mile mark 8.155 seconds
MPH – 83.85
1000 feet mark 10.663 seconds
1/4 mile mark 12.816 seconds
Final MPH – 105. 27

I'm looking to come up with a polynomial equation that calculates the vehicle's position with respect to time as accurately as possible. In addition, it needs to differentiate to velocity and acceleration.

If you have any contribution, please submit it! Anything that helps me find a workable process helps. You guys rock!

This is rather a complex problem which does not have a simple solution. The ordinary equations of motion do not apply because the acceleration is anything but uniform.

I first convert all distances to feet, and speeds to feet per second. The first table shows the given data at each checkpoint, together with a simple calculation of the average speed from the start-line up to that point (distance / time). The last column shows the increments in speed over each section. They show that acceleration decreases rapidly over successive sections.

Table 1
=====.... .... ..... ....Time (s) ..D (ft) ...Av. spd ..... Diff

Start ..... .... ..... ..... 0.00 ..... 000 ..... 00.00

..... 1 .... ..... .... .....1.724 ...... 60 ..... 34.80 ..... 34.80

..... 2 ..... ..... ..... ...5.185 .... 330 ..... 63.65 ..... 28.85

..... 3 ..... .... .... .... 8.155 .... 660 ..... 80.93 ..... 17.28

..... 4 ..... ..... ..... .10.633 ... 1000 .... 94.05 ...... 13.12

..... 5 ..... ..... ...... 12.816 ... 1320 .. 103.00 .... ... 8.95

The second table shows the average speed calculated for each section individually. This again shows that, although speed keeps increasing, the rate at which it increases (the acceleration) falls off rapidly (which I found rather surprising - is this the usual way of things?)

Table 2
=====.... .... ..... ....Time (s) ..D (ft) ...Av. spd ... Acceln.

0 - 1 .... ..... .... .....1.724 ...... 60 ..... 34.80 ...... 20.19

1 - 2 ..... ..... ..... ...3.461 .... 270 ..... 78.01 ...... 12.48

2 - 3 ..... .... .... .... 2.970 .... 330 .... 111.11 ..... 11.14

3 - 4 ..... ..... ..... .. 2.478 .... 340 .... 137.21 ..... 10.53

4 - 5 ..... ..... ...... . 2.183 .... 320 .... 146.59 .... ...4.30

The last column shows the average acceleration over each section calculated from the equation v = u + at (the motion over a short span is more uniform, so these are better estimates of the actual situation than those in table 1).

A plotting program gave an equation of best fit for the points given :

y = 5x² + 41.4x - 11.7 (x represents time, y represents distance, of course)

which is a reasonably good fit over the middle section, where the motion is settling down somewhat ( the 1 to 2 seconds at the start are obviously a period of rapidly-changing conditions, and probably need a completely different equation to describe them, but without any data within this time it is impossible to suggest what it might be.) The equation shows some divergence towards the end of the run, by about 1.5%.

Differentiating, dy / dx = 10x + 41.4, which gives speed of 123 ft/sec at t = 8.155 sec, which matches exactly the speed check at the 660 feet mark (83.85 mph = 123.00 ft/sec); at 12.816 sec the calculated speed is 169.56 ft/sec, rather higher than the speed check at the end of the run (105.27 mph = 154.40 ft/sec).

The motion is clearly far from uniform, and a single equation could not describe the complete run with any accuracy. I do not think that a single equation would be applicable to every run, even of the same vehicle. It must be impossible to replicate the same conditions for every run, because each run will alter the condition of the track, of the tyres, and the engine tune must differ over time when operated near its peak. Each run of each vehicle would probably give rise to a completely different equation.

(Conversion factor for speed : 60 mph = 88 ft/sec exactly, so 1 mph = 88/60 ft/sec, hence v mph = 88v/60 ft/sec )

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PROFORM PERFECT LAUNCH DRAG PRACTICE DRAG RACING TREE REACTION TIME TRIGGER

US $52.00

18d 23h 2m

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What is the Reaction Time for NHRA Drag Racing Measured In?

I was doing a reaction time test and i got a best time of .4 but i noticed in NHRA racing they get like 0.0XX numbers. I read this on a website: "that program is still going by the .500 index rather than .000..." Is this right, and true?
And if this is true, what is the conversion? A formula???

Reaction time is based on seconds or more correctly fractions of a second.

There are 4 tenths (.400 of a second) and 5 tenths trees (.500 of a second). These times are the time between the lighting of the last yellow light and the lighting of the green light.

On a 4 tenths tree the best reaction time would be .400 meaning the car left exactly when the green light came on. A reaction time of .300 would be a red light from the car leaving before the green light came on. A .410 reaction time would be good. .600 would be very bad meaning the light was green .2 of a second before the car moved.

Because of the differently timed trees reaction times were difficult to understand, especially for fans. New electronics have allowed them to give the reaction time based on the green light rather than the time from the last yellow light. So on a 4 tenths tree a perfect start would be .000 instead of .400 and a .410 becomes a .010 A perfect light on a 5 tenths tree would also be a .000 making everything easier to understand and compare.

If your .4 is based on a 4 tenths tree then that is a perfect light or .000 If it is a 5 tenths tree then that would be a red light. If your .4 time came from the new .000 system then it is very slow.

The conversion would be subtracting .400 from your time on a 4 tenths tree or subtracting .500 from your time on a 5 tenths tree.

Remember it's one thing to push a button to get a simulated reaction and a completely different thing to stage a race car and make the front tires expose the light beam just as the green light comes on.

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